Base | Representation |
---|---|
bin | 11000100110111010… |
… | …01100111111011101 |
3 | 1021002201102211000102 |
4 | 30103131030333131 |
5 | 204024044340011 |
6 | 10022540310445 |
7 | 645250255463 |
oct | 142335147735 |
9 | 37081384012 |
10 | 13211324381 |
11 | 566a4a2602 |
12 | 2688542425 |
13 | 13270c2608 |
14 | 8d4858833 |
15 | 524c9673b |
hex | 31374cfdd |
13211324381 has 2 divisors, whose sum is σ = 13211324382. Its totient is φ = 13211324380.
The previous prime is 13211324369. The next prime is 13211324447. The reversal of 13211324381 is 18342311231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8824911481 + 4386412900 = 93941^2 + 66230^2 .
It is a cyclic number.
It is not a de Polignac number, because 13211324381 - 210 = 13211323357 is a prime.
It is a super-2 number, since 2×132113243812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13211324311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605662190 + 6605662191.
It is an arithmetic number, because the mean of its divisors is an integer number (6605662191).
Almost surely, 213211324381 is an apocalyptic number.
It is an amenable number.
13211324381 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211324381 is an equidigital number, since it uses as much as digits as its factorization.
13211324381 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3456, while the sum is 29.
The spelling of 13211324381 in words is "thirteen billion, two hundred eleven million, three hundred twenty-four thousand, three hundred eighty-one".
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