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132114140213417 is a prime number
BaseRepresentation
bin11110000010100000111000…
…011001011011000010101001
3122022202222200120210202012122
4132002200320121123002221
5114304024224343312132
61144552221555521025
736553634361053165
oct3602407031330251
9568688616722178
10132114140213417
1139106323a3a7aa
12129987322b9175
135894404cbb37b
14248a503a43ca5
1510418d2d8d912
hex78283865b0a9

132114140213417 has 2 divisors, whose sum is σ = 132114140213418. Its totient is φ = 132114140213416.

The previous prime is 132114140213371. The next prime is 132114140213441. The reversal of 132114140213417 is 714312041411231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125363761987216 + 6750378226201 = 11196596^2 + 2598149^2 .

It is a cyclic number.

It is not a de Polignac number, because 132114140213417 - 28 = 132114140213161 is a prime.

It is not a weakly prime, because it can be changed into another prime (132114140713417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057070106708 + 66057070106709.

It is an arithmetic number, because the mean of its divisors is an integer number (66057070106709).

Almost surely, 2132114140213417 is an apocalyptic number.

It is an amenable number.

132114140213417 is a deficient number, since it is larger than the sum of its proper divisors (1).

132114140213417 is an equidigital number, since it uses as much as digits as its factorization.

132114140213417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 35.

Adding to 132114140213417 its reverse (714312041411231), we get a palindrome (846426181624648).

The spelling of 132114140213417 in words is "one hundred thirty-two trillion, one hundred fourteen billion, one hundred forty million, two hundred thirteen thousand, four hundred seventeen".