Base | Representation |
---|---|
bin | 11110000010100000111101… |
… | …110000011110110100111101 |
3 | 122022202222220212000201012201 |
4 | 132002200331300132310331 |
5 | 114304024420404104232 |
6 | 1144552234531231501 |
7 | 36553636532340331 |
oct | 3602407560366475 |
9 | 568688825021181 |
10 | 132114230144317 |
11 | 3910636a784163 |
12 | 12998758448591 |
13 | 589441a817a15 |
14 | 248a5119737c1 |
15 | 10418dac04be7 |
hex | 78283dc1ed3d |
132114230144317 has 2 divisors, whose sum is σ = 132114230144318. Its totient is φ = 132114230144316.
The previous prime is 132114230144263. The next prime is 132114230144321. The reversal of 132114230144317 is 713441032411231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130866141226276 + 1248088918041 = 11439674^2 + 1117179^2 .
It is a cyclic number.
It is not a de Polignac number, because 132114230144317 - 27 = 132114230144189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132114230142317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057115072158 + 66057115072159.
It is an arithmetic number, because the mean of its divisors is an integer number (66057115072159).
Almost surely, 2132114230144317 is an apocalyptic number.
It is an amenable number.
132114230144317 is a deficient number, since it is larger than the sum of its proper divisors (1).
132114230144317 is an equidigital number, since it uses as much as digits as its factorization.
132114230144317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 37.
Adding to 132114230144317 its reverse (713441032411231), we get a palindrome (845555262555548).
The spelling of 132114230144317 in words is "one hundred thirty-two trillion, one hundred fourteen billion, two hundred thirty million, one hundred forty-four thousand, three hundred seventeen".
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