Base | Representation |
---|---|
bin | 11110000010100001001010… |
… | …010110000101110111011111 |
3 | 122022210000110120102001200222 |
4 | 132002201022112011313133 |
5 | 114304030333440031033 |
6 | 1144552311513511555 |
7 | 36553645005363416 |
oct | 3602411226056737 |
9 | 568700416361628 |
10 | 132114441330143 |
11 | 39106468a071a8 |
12 | 129987b71125bb |
13 | 58944524ba54c |
14 | 248a531a2847d |
15 | 10418ee51d598 |
hex | 78284a585ddf |
132114441330143 has 8 divisors (see below), whose sum is σ = 132316556078976. Its totient is φ = 131912457616800.
The previous prime is 132114441330133. The next prime is 132114441330161. The reversal of 132114441330143 is 341033144411231.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132114441330143 - 212 = 132114441326047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132114441330103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30740768 + ... + 34773893.
It is an arithmetic number, because the mean of its divisors is an integer number (16539569509872).
Almost surely, 2132114441330143 is an apocalyptic number.
132114441330143 is a deficient number, since it is larger than the sum of its proper divisors (202114748833).
132114441330143 is an equidigital number, since it uses as much as digits as its factorization.
132114441330143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65517745.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 132114441330143 its reverse (341033144411231), we get a palindrome (473147585741374).
The spelling of 132114441330143 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-one million, three hundred thirty thousand, one hundred forty-three".
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