Base | Representation |
---|---|
bin | 11110000010100001001010… |
… | …010110000101110111011110 |
3 | 122022210000110120102001200221 |
4 | 132002201022112011313132 |
5 | 114304030333440031032 |
6 | 1144552311513511554 |
7 | 36553645005363415 |
oct | 3602411226056736 |
9 | 568700416361627 |
10 | 132114441330142 |
11 | 39106468a071a7 |
12 | 129987b71125ba |
13 | 58944524ba54b |
14 | 248a531a2847c |
15 | 10418ee51d597 |
hex | 78284a585dde |
132114441330142 has 32 divisors (see below), whose sum is σ = 199740063768192. Its totient is φ = 65536347469824.
The previous prime is 132114441330133. The next prime is 132114441330161. The reversal of 132114441330142 is 241033144411231.
It is a junction number, because it is equal to n+sod(n) for n = 132114441330098 and 132114441330107.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 791717988 + ... + 791884840.
It is an arithmetic number, because the mean of its divisors is an integer number (6241876992756).
Almost surely, 2132114441330142 is an apocalyptic number.
132114441330142 is a deficient number, since it is larger than the sum of its proper divisors (67625622438050).
132114441330142 is a wasteful number, since it uses less digits than its factorization.
132114441330142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 172612.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 132114441330142 its reverse (241033144411231), we get a palindrome (373147585741373).
The spelling of 132114441330142 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-one million, three hundred thirty thousand, one hundred forty-two".
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