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13212000047 is a prime number
BaseRepresentation
bin11000100110111111…
…10001111100101111
31021002202201010212002
430103133301330233
5204024233000142
610023003002515
7645256101401
oct142337617457
937082633762
1013212000047
11566a914204
12268880943b
13132729b00c
148d4992b71
15524d7ba32
hex3137f1f2f

13212000047 has 2 divisors, whose sum is σ = 13212000048. Its totient is φ = 13212000046.

The previous prime is 13212000029. The next prime is 13212000059. The reversal of 13212000047 is 74000021231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13212000047 - 28 = 13211999791 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13211999992 and 13212000028.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13212000017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606000023 + 6606000024.

It is an arithmetic number, because the mean of its divisors is an integer number (6606000024).

Almost surely, 213212000047 is an apocalyptic number.

13212000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212000047 is an equidigital number, since it uses as much as digits as its factorization.

13212000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336, while the sum is 20.

Adding to 13212000047 its reverse (74000021231), we get a palindrome (87212021278).

The spelling of 13212000047 in words is "thirteen billion, two hundred twelve million, forty-seven", and thus it is an aban number.