Base | Representation |
---|---|
bin | 11110000010100110011100… |
… | …010010100011100010010111 |
3 | 122022210120002201002022200001 |
4 | 132002212130102203202113 |
5 | 114304123441420231403 |
6 | 1144555050252432131 |
7 | 36554235342554005 |
oct | 3602463422434227 |
9 | 568716081068601 |
10 | 132120111102103 |
11 | 39108908397853 |
12 | 12999919a78647 |
13 | 5894b470337b7 |
14 | 248a90ca35a75 |
15 | 1041b32175c1d |
hex | 78299c4a3897 |
132120111102103 has 2 divisors, whose sum is σ = 132120111102104. Its totient is φ = 132120111102102.
The previous prime is 132120111102043. The next prime is 132120111102107. The reversal of 132120111102103 is 301201111021231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132120111102103 - 29 = 132120111101591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132120111102107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060055551051 + 66060055551052.
It is an arithmetic number, because the mean of its divisors is an integer number (66060055551052).
Almost surely, 2132120111102103 is an apocalyptic number.
132120111102103 is a deficient number, since it is larger than the sum of its proper divisors (1).
132120111102103 is an equidigital number, since it uses as much as digits as its factorization.
132120111102103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 132120111102103 its reverse (301201111021231), we get a palindrome (433321222123334).
The spelling of 132120111102103 in words is "one hundred thirty-two trillion, one hundred twenty billion, one hundred eleven million, one hundred two thousand, one hundred three".
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