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13212012014 = 26606006007
BaseRepresentation
bin11000100110111111…
…10100110111101110
31021002202201202021022
430103133310313232
5204024233341024
610023003134142
7645256151315
oct142337646756
937082652238
1013212012014
11566a9221a3
122688814352
1313272a35b6
148d499727c
15524d8035e
hex3137f4dee

13212012014 has 4 divisors (see below), whose sum is σ = 19818018024. Its totient is φ = 6606006006.

The previous prime is 13212012001. The next prime is 13212012031. The reversal of 13212012014 is 41021021231.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×132120120142 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13212011983 and 13212012001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303003002 + ... + 3303003005.

It is an arithmetic number, because the mean of its divisors is an integer number (4954504506).

Almost surely, 213212012014 is an apocalyptic number.

13212012014 is a deficient number, since it is larger than the sum of its proper divisors (6606006010).

13212012014 is an equidigital number, since it uses as much as digits as its factorization.

13212012014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6606006009.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 13212012014 its reverse (41021021231), we get a palindrome (54233033245).

The spelling of 13212012014 in words is "thirteen billion, two hundred twelve million, twelve thousand, fourteen".

Divisors: 1 2 6606006007 13212012014