Base | Representation |
---|---|
bin | 11110000010100110011110… |
… | …010000000011100001100011 |
3 | 122022210120011222222202122021 |
4 | 132002212132100003201203 |
5 | 114304124023331013443 |
6 | 1144555053425522311 |
7 | 36554236222315345 |
oct | 3602463620034143 |
9 | 568716158882567 |
10 | 132120144001123 |
11 | 39108924a18323 |
12 | 12999928aa3397 |
13 | 5894b50ab2185 |
14 | 248a91315b295 |
15 | 1041b34ec39ed |
hex | 78299e403863 |
132120144001123 has 2 divisors, whose sum is σ = 132120144001124. Its totient is φ = 132120144001122.
The previous prime is 132120144001103. The next prime is 132120144001147. The reversal of 132120144001123 is 321100441021231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132120144001123 - 25 = 132120144001091 is a prime.
It is a super-2 number, since 2×1321201440011232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132120144001103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060072000561 + 66060072000562.
It is an arithmetic number, because the mean of its divisors is an integer number (66060072000562).
Almost surely, 2132120144001123 is an apocalyptic number.
132120144001123 is a deficient number, since it is larger than the sum of its proper divisors (1).
132120144001123 is an equidigital number, since it uses as much as digits as its factorization.
132120144001123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 132120144001123 its reverse (321100441021231), we get a palindrome (453220585022354).
The spelling of 132120144001123 in words is "one hundred thirty-two trillion, one hundred twenty billion, one hundred forty-four million, one thousand, one hundred twenty-three".
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