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132120144013201 is a prime number
BaseRepresentation
bin11110000010100110011110…
…010000000110011110010001
3122022210120012000000101012121
4132002212132100012132101
5114304124023331410301
61144555053430054241
736554236222365511
oct3602463620063621
9568716160011177
10132120144013201
1139108924a26403
1212999928aaa381
135894b50ab7816
14248a913161841
151041b34ec73a1
hex78299e406791

132120144013201 has 2 divisors, whose sum is σ = 132120144013202. Its totient is φ = 132120144013200.

The previous prime is 132120144013171. The next prime is 132120144013243. The reversal of 132120144013201 is 102310441021231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87825462082576 + 44294681930625 = 9371524^2 + 6655425^2 .

It is a cyclic number.

It is not a de Polignac number, because 132120144013201 - 223 = 132120135624593 is a prime.

It is not a weakly prime, because it can be changed into another prime (132120144013901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060072006600 + 66060072006601.

It is an arithmetic number, because the mean of its divisors is an integer number (66060072006601).

Almost surely, 2132120144013201 is an apocalyptic number.

It is an amenable number.

132120144013201 is a deficient number, since it is larger than the sum of its proper divisors (1).

132120144013201 is an equidigital number, since it uses as much as digits as its factorization.

132120144013201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 132120144013201 its reverse (102310441021231), we get a palindrome (234430585034432).

The spelling of 132120144013201 in words is "one hundred thirty-two trillion, one hundred twenty billion, one hundred forty-four million, thirteen thousand, two hundred one".