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13212064535 = 52642412907
BaseRepresentation
bin11000100111000000…
…00001101100010111
31021002202211102022112
430103200001230113
5204024242031120
610023004221235
7645256460405
oct142340015427
937082742275
1013212064535
11566a9586aa
12268883a81b
1313272c1487
148d49ac475
15524d90bc5
hex313801b17

13212064535 has 4 divisors (see below), whose sum is σ = 15854477448. Its totient is φ = 10569651624.

The previous prime is 13212064511. The next prime is 13212064543. The reversal of 13212064535 is 53546021231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53546021231 = 371447189763.

It is a cyclic number.

It is not a de Polignac number, because 13212064535 - 220 = 13211015959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321206449 + ... + 1321206458.

It is an arithmetic number, because the mean of its divisors is an integer number (3963619362).

Almost surely, 213212064535 is an apocalyptic number.

13212064535 is a deficient number, since it is larger than the sum of its proper divisors (2642412913).

13212064535 is an equidigital number, since it uses as much as digits as its factorization.

13212064535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2642412912.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 13212064535 its reverse (53546021231), we get a palindrome (66758085766).

The spelling of 13212064535 in words is "thirteen billion, two hundred twelve million, sixty-four thousand, five hundred thirty-five".

Divisors: 1 5 2642412907 13212064535