Base | Representation |
---|---|
bin | 11110000010100111010010… |
… | …000010111110001111011111 |
3 | 122022210122102120010210221201 |
4 | 132002213102002332033133 |
5 | 114304132313311034342 |
6 | 1144555315551140331 |
7 | 36554266603502413 |
oct | 3602472202761737 |
9 | 568718376123851 |
10 | 132121012986847 |
11 | 39109230497145 |
12 | 12999b2bb146a7 |
13 | 5894c5bb3a001 |
14 | 248a996722d43 |
15 | 1041b86425db7 |
hex | 7829d20be3df |
132121012986847 has 2 divisors, whose sum is σ = 132121012986848. Its totient is φ = 132121012986846.
The previous prime is 132121012986773. The next prime is 132121012986869. The reversal of 132121012986847 is 748689210121231.
It is a strong prime.
It is an emirp because it is prime and its reverse (748689210121231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132121012986847 - 227 = 132120878769119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132121012981847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060506493423 + 66060506493424.
It is an arithmetic number, because the mean of its divisors is an integer number (66060506493424).
Almost surely, 2132121012986847 is an apocalyptic number.
132121012986847 is a deficient number, since it is larger than the sum of its proper divisors (1).
132121012986847 is an equidigital number, since it uses as much as digits as its factorization.
132121012986847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2322432, while the sum is 55.
The spelling of 132121012986847 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, twelve million, nine hundred eighty-six thousand, eight hundred forty-seven".
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