Base | Representation |
---|---|
bin | 11110000010100111010111… |
… | …010111101110001001110011 |
3 | 122022210122122210020000002121 |
4 | 132002213113113232021303 |
5 | 114304133004142441201 |
6 | 1144555332501455111 |
7 | 36554302036654636 |
oct | 3602472727561163 |
9 | 568718583200077 |
10 | 132121102312051 |
11 | 39109276957526 |
12 | 12999b55a11497 |
13 | 5894c744b3a68 |
14 | 248a9a4535c1d |
15 | 1041b8e1bc9a1 |
hex | 7829d75ee273 |
132121102312051 has 2 divisors, whose sum is σ = 132121102312052. Its totient is φ = 132121102312050.
The previous prime is 132121102312037. The next prime is 132121102312081. The reversal of 132121102312051 is 150213201121231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132121102312051 - 233 = 132112512377459 is a prime.
It is not a weakly prime, because it can be changed into another prime (132121102312081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060551156025 + 66060551156026.
It is an arithmetic number, because the mean of its divisors is an integer number (66060551156026).
Almost surely, 2132121102312051 is an apocalyptic number.
132121102312051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132121102312051 is an equidigital number, since it uses as much as digits as its factorization.
132121102312051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 132121102312051 its reverse (150213201121231), we get a palindrome (282334303433282).
The spelling of 132121102312051 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, one hundred two million, three hundred twelve thousand, fifty-one".
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