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132122102113 is a prime number
BaseRepresentation
bin111101100001100010…
…1110100100101100001
3110122000211001012110101
41323003011310211201
54131041224231423
6140410203102401
712355052223661
oct1730305644541
9418024035411
10132122102113
115103a533931
1221733511a01
13c5c7730861
14657526a1a1
1536842e47ad
hex1ec3174961

132122102113 has 2 divisors, whose sum is σ = 132122102114. Its totient is φ = 132122102112.

The previous prime is 132122102111. The next prime is 132122102141. The reversal of 132122102113 is 311201221231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111658227409 + 20463874704 = 334153^2 + 143052^2 .

It is a cyclic number.

It is not a de Polignac number, because 132122102113 - 21 = 132122102111 is a prime.

Together with 132122102111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (132122102111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061051056 + 66061051057.

It is an arithmetic number, because the mean of its divisors is an integer number (66061051057).

Almost surely, 2132122102113 is an apocalyptic number.

It is an amenable number.

132122102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132122102113 is an equidigital number, since it uses as much as digits as its factorization.

132122102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132122102113 its reverse (311201221231), we get a palindrome (443323323344).

The spelling of 132122102113 in words is "one hundred thirty-two billion, one hundred twenty-two million, one hundred two thousand, one hundred thirteen".