Base | Representation |
---|---|
bin | 11110000010101001100001… |
… | …100101110001111100011101 |
3 | 122022210212122101201102121102 |
4 | 132002221201211301330131 |
5 | 114304202231320102110 |
6 | 1145000354540442445 |
7 | 36554413355435621 |
oct | 3602514145617435 |
9 | 568725571642542 |
10 | 132123421253405 |
11 | 3910a25693548a |
12 | 1299a4a2549425 |
13 | 5895253a5b4ca |
14 | 248ab444d5181 |
15 | 1041c77a815a5 |
hex | 782a61971f1d |
132123421253405 has 64 divisors (see below), whose sum is σ = 174498153984000. Its totient is φ = 95590054264320.
The previous prime is 132123421253389. The next prime is 132123421253449. The reversal of 132123421253405 is 504352124321231.
It is not a de Polignac number, because 132123421253405 - 24 = 132123421253389 is a prime.
It is a super-2 number, since 2×1321234212534052 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2216397050 + ... + 2216456660.
It is an arithmetic number, because the mean of its divisors is an integer number (2726533656000).
Almost surely, 2132123421253405 is an apocalyptic number.
It is an amenable number.
132123421253405 is a deficient number, since it is larger than the sum of its proper divisors (42374732730595).
132123421253405 is a wasteful number, since it uses less digits than its factorization.
132123421253405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61674.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 132123421253405 its reverse (504352124321231), we get a palindrome (636475545574636).
The spelling of 132123421253405 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, four hundred twenty-one million, two hundred fifty-three thousand, four hundred five".
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