Base | Representation |
---|---|
bin | 111101100001101001… |
… | …1100011100101101011 |
3 | 110122001001211010021022 |
4 | 1323003103203211223 |
5 | 4131043134440012 |
6 | 140410412203055 |
7 | 12355124640521 |
oct | 1730323434553 |
9 | 418031733238 |
10 | 132125702507 |
11 | 51041572967 |
12 | 2173476948b |
13 | c5c83c1576 |
14 | 6575926311 |
15 | 36847a6472 |
hex | 1ec34e396b |
132125702507 has 2 divisors, whose sum is σ = 132125702508. Its totient is φ = 132125702506.
The previous prime is 132125702483. The next prime is 132125702509. The reversal of 132125702507 is 705207521231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132125702507 - 234 = 114945833323 is a prime.
Together with 132125702509, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132125702509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66062851253 + 66062851254.
It is an arithmetic number, because the mean of its divisors is an integer number (66062851254).
Almost surely, 2132125702507 is an apocalyptic number.
132125702507 is a deficient number, since it is larger than the sum of its proper divisors (1).
132125702507 is an equidigital number, since it uses as much as digits as its factorization.
132125702507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29400, while the sum is 35.
The spelling of 132125702507 in words is "one hundred thirty-two billion, one hundred twenty-five million, seven hundred two thousand, five hundred seven".
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