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13212639113 is a prime number
BaseRepresentation
bin11000100111000100…
…01101111110001001
31021002210220121111012
430103202031332021
5204024413422423
610023024413305
7645264402512
oct142342157611
937083817435
1013212639113
115670210363
122688a77235
131327462b6b
148d4abba09
15524e56078
hex31388df89

13212639113 has 2 divisors, whose sum is σ = 13212639114. Its totient is φ = 13212639112.

The previous prime is 13212639073. The next prime is 13212639119. The reversal of 13212639113 is 31193621231.

13212639113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7437855049 + 5774784064 = 86243^2 + 75992^2 .

It is a cyclic number.

It is not a de Polignac number, because 13212639113 - 224 = 13195861897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13212639113.

It is not a weakly prime, because it can be changed into another prime (13212639119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606319556 + 6606319557.

It is an arithmetic number, because the mean of its divisors is an integer number (6606319557).

Almost surely, 213212639113 is an apocalyptic number.

It is an amenable number.

13212639113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212639113 is an equidigital number, since it uses as much as digits as its factorization.

13212639113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832, while the sum is 32.

The spelling of 13212639113 in words is "thirteen billion, two hundred twelve million, six hundred thirty-nine thousand, one hundred thirteen".