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132130032212147 is a prime number
BaseRepresentation
bin11110000010101111101011…
…101000100101100010110011
3122022211111201010101221010012
4132002233223220211202303
5114304304301221242042
61145003410540325135
736555036241605044
oct3602575350454263
9568744633357105
10132130032212147
1139112039619652
121299b8285437ab
135895a6858bc08
14248b1b05008cb
15104201314de82
hex782beba258b3

132130032212147 has 2 divisors, whose sum is σ = 132130032212148. Its totient is φ = 132130032212146.

The previous prime is 132130032212117. The next prime is 132130032212161. The reversal of 132130032212147 is 741212230031231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132130032212147 - 230 = 132128958470323 is a prime.

It is not a weakly prime, because it can be changed into another prime (132130032212117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065016106073 + 66065016106074.

It is an arithmetic number, because the mean of its divisors is an integer number (66065016106074).

Almost surely, 2132130032212147 is an apocalyptic number.

132130032212147 is a deficient number, since it is larger than the sum of its proper divisors (1).

132130032212147 is an equidigital number, since it uses as much as digits as its factorization.

132130032212147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 132130032212147 its reverse (741212230031231), we get a palindrome (873342262243378).

The spelling of 132130032212147 in words is "one hundred thirty-two trillion, one hundred thirty billion, thirty-two million, two hundred twelve thousand, one hundred forty-seven".