Search a number
-
+
132130311100000 = 2555193111511949
BaseRepresentation
bin11110000010101111111100…
…010000011101011001100000
3122022211112102120011220022221
4132002233330100131121200
5114304310334120200000
61145003454342040424
736555046166244133
oct3602577420353140
9568745376156287
10132130311100000
1139112171a93184
121299b8a5a19114
135895ab12a7305
14248b1d957a21a
15104202c88c61a
hex782bfc41d660

132130311100000 has 576 divisors, whose sum is σ = 353785356288000. Its totient is φ = 48388320000000.

The previous prime is 132130311099979. The next prime is 132130311100003. The reversal of 132130311100000 is 1113031231.

It is a super-2 number, since 2×1321303111000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132130311100003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 67793899026 + ... + 67793900974.

It is an arithmetic number, because the mean of its divisors is an integer number (614210688000).

Almost surely, 2132130311100000 is an apocalyptic number.

132130311100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132130311100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176892678144000).

132130311100000 is an abundant number, since it is smaller than the sum of its proper divisors (221655045188000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132130311100000 is a wasteful number, since it uses less digits than its factorization.

132130311100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3185 (or 3157 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 132130311100000 its reverse (1113031231), we get a palindrome (132131424131231).

The spelling of 132130311100000 in words is "one hundred thirty-two trillion, one hundred thirty billion, three hundred eleven million, one hundred thousand".