Base | Representation |
---|---|
bin | 10011001110100100001… |
… | …111010011100001010110 |
3 | 11200022112101200201220212 |
4 | 103032210033103201112 |
5 | 133122020432413124 |
6 | 2451000204125422 |
7 | 164314206250604 |
oct | 23164417234126 |
9 | 4608471621825 |
10 | 1321310435414 |
11 | 46a401326792 |
12 | 1940b4236872 |
13 | 977a3121b38 |
14 | 47d4790a874 |
15 | 24584c4340e |
hex | 133a43d3856 |
1321310435414 has 4 divisors (see below), whose sum is σ = 1981965653124. Its totient is φ = 660655217706.
The previous prime is 1321310435411. The next prime is 1321310435441. The reversal of 1321310435414 is 4145340131231.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×13213104354142 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1321310435411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330327608852 + ... + 330327608855.
It is an arithmetic number, because the mean of its divisors is an integer number (495491413281).
Almost surely, 21321310435414 is an apocalyptic number.
1321310435414 is a deficient number, since it is larger than the sum of its proper divisors (660655217710).
1321310435414 is an equidigital number, since it uses as much as digits as its factorization.
1321310435414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 660655217709.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 1321310435414 its reverse (4145340131231), we get a palindrome (5466650566645).
The spelling of 1321310435414 in words is "one trillion, three hundred twenty-one billion, three hundred ten million, four hundred thirty-five thousand, four hundred fourteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •