Base | Representation |
---|---|
bin | 111101100001110100… |
… | …1110110011111111010 |
3 | 110122001110211001120211 |
4 | 1323003221312133322 |
5 | 4131101134002010 |
6 | 140411141341334 |
7 | 12355225422322 |
oct | 1730351663772 |
9 | 418043731524 |
10 | 132131547130 |
11 | 510448a5030 |
12 | 2173670784a |
13 | c5c968991b |
14 | 6576608282 |
15 | 368505d08a |
hex | 1ec3a767fa |
132131547130 has 32 divisors (see below), whose sum is σ = 261324947520. Its totient is φ = 47702161920.
The previous prime is 132131547103. The next prime is 132131547131. The reversal of 132131547130 is 31745131231.
It is a super-2 number, since 2×1321315471302 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132131547092 and 132131547101.
It is not an unprimeable number, because it can be changed into a prime (132131547131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4305559 + ... + 4336138.
It is an arithmetic number, because the mean of its divisors is an integer number (8166404610).
Almost surely, 2132131547130 is an apocalyptic number.
132131547130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132131547130 is a deficient number, since it is larger than the sum of its proper divisors (129193400390).
132131547130 is a wasteful number, since it uses less digits than its factorization.
132131547130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8641854.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 132131547130 its reverse (31745131231), we get a palindrome (163876678361).
The spelling of 132131547130 in words is "one hundred thirty-two billion, one hundred thirty-one million, five hundred forty-seven thousand, one hundred thirty".
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