Base | Representation |
---|---|
bin | 11110000010110001100111… |
… | …000100000011101111100111 |
3 | 122022211201001102222102112020 |
4 | 132002301213010003233213 |
5 | 114304323021332330203 |
6 | 1145004352232554223 |
7 | 36555141455242263 |
oct | 3602614704035747 |
9 | 568751042872466 |
10 | 132132103011303 |
11 | 39112a0152270a |
12 | 129a0105b52973 |
13 | 58960085c4765 |
14 | 248b3295490a3 |
15 | 10420d4d49153 |
hex | 782c67103be7 |
132132103011303 has 8 divisors (see below), whose sum is σ = 176311970921328. Its totient is φ = 88020151887744.
The previous prime is 132132103011301. The next prime is 132132103011317. The reversal of 132132103011303 is 303110301231231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132132103011303 - 21 = 132132103011301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132132103011301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16979192076 + ... + 16979199857.
It is an arithmetic number, because the mean of its divisors is an integer number (22038996365166).
Almost surely, 2132132103011303 is an apocalyptic number.
132132103011303 is a deficient number, since it is larger than the sum of its proper divisors (44179867910025).
132132103011303 is a wasteful number, since it uses less digits than its factorization.
132132103011303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33958393233.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 132132103011303 its reverse (303110301231231), we get a palindrome (435242404242534).
The spelling of 132132103011303 in words is "one hundred thirty-two trillion, one hundred thirty-two billion, one hundred three million, eleven thousand, three hundred three".
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