Base | Representation |
---|---|
bin | 111101100001110110… |
… | …1001001010100111001 |
3 | 110122001112102221011012 |
4 | 1323003231021110321 |
5 | 4131101344120211 |
6 | 140411212043305 |
7 | 12355235650055 |
oct | 1730355112471 |
9 | 418045387135 |
10 | 132132410681 |
11 | 51045334907 |
12 | 21736a63535 |
13 | c5c98cc9bb |
14 | 6576790c65 |
15 | 368517dd8b |
hex | 1ec3b49539 |
132132410681 has 2 divisors, whose sum is σ = 132132410682. Its totient is φ = 132132410680.
The previous prime is 132132410671. The next prime is 132132410759. The reversal of 132132410681 is 186014231231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 76540202281 + 55592208400 = 276659^2 + 235780^2 .
It is a cyclic number.
It is not a de Polignac number, because 132132410681 - 26 = 132132410617 is a prime.
It is a super-2 number, since 2×1321324106812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132132410611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66066205340 + 66066205341.
It is an arithmetic number, because the mean of its divisors is an integer number (66066205341).
Almost surely, 2132132410681 is an apocalyptic number.
It is an amenable number.
132132410681 is a deficient number, since it is larger than the sum of its proper divisors (1).
132132410681 is an equidigital number, since it uses as much as digits as its factorization.
132132410681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 32.
The spelling of 132132410681 in words is "one hundred thirty-two billion, one hundred thirty-two million, four hundred ten thousand, six hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •