Base | Representation |
---|---|
bin | 10011001110100101100… |
… | …101111010111110101101 |
3 | 11200022120222102022201002 |
4 | 103032211211322332231 |
5 | 133122042241011141 |
6 | 2451002334530045 |
7 | 164314603250066 |
oct | 23164545727655 |
9 | 4608528368632 |
10 | 1321333141421 |
11 | 46a413125087 |
12 | 1940bb966925 |
13 | 977a7a41b47 |
14 | 47d4a93b56d |
15 | 24586c2ae9b |
hex | 133a597afad |
1321333141421 has 2 divisors, whose sum is σ = 1321333141422. Its totient is φ = 1321333141420.
The previous prime is 1321333141409. The next prime is 1321333141441. The reversal of 1321333141421 is 1241413331231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 738422269225 + 582910872196 = 859315^2 + 763486^2 .
It is a cyclic number.
It is not a de Polignac number, because 1321333141421 - 210 = 1321333140397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321333141441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660666570710 + 660666570711.
It is an arithmetic number, because the mean of its divisors is an integer number (660666570711).
Almost surely, 21321333141421 is an apocalyptic number.
It is an amenable number.
1321333141421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321333141421 is an equidigital number, since it uses as much as digits as its factorization.
1321333141421 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 29.
Adding to 1321333141421 its reverse (1241413331231), we get a palindrome (2562746472652).
The spelling of 1321333141421 in words is "one trillion, three hundred twenty-one billion, three hundred thirty-three million, one hundred forty-one thousand, four hundred twenty-one".
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