Base | Representation |
---|---|
bin | 11110000010110011011010… |
… | …110001111111010000110010 |
3 | 122022211220001202002210020122 |
4 | 132002303122301333100302 |
5 | 114304341010333301120 |
6 | 1145005313024210242 |
7 | 36555240541113230 |
oct | 3602633261772062 |
9 | 568756052083218 |
10 | 132134044431410 |
11 | 3911380839933a |
12 | 129a0568169982 |
13 | 589625789b358 |
14 | 248b471315950 |
15 | 104219a4d9a25 |
hex | 782cdac7f432 |
132134044431410 has 32 divisors (see below), whose sum is σ = 275542148241792. Its totient is φ = 44682510522240.
The previous prime is 132134044431353. The next prime is 132134044431421. The reversal of 132134044431410 is 14134440431231.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12928962056 + ... + 12928972275.
It is an arithmetic number, because the mean of its divisors is an integer number (8610692132556).
Almost surely, 2132134044431410 is an apocalyptic number.
132134044431410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132134044431410 is an abundant number, since it is smaller than the sum of its proper divisors (143408103810382).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132134044431410 is a wasteful number, since it uses less digits than its factorization.
132134044431410 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25857934418.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 132134044431410 its reverse (14134440431231), we get a palindrome (146268484862641).
The spelling of 132134044431410 in words is "one hundred thirty-two trillion, one hundred thirty-four billion, forty-four million, four hundred thirty-one thousand, four hundred ten".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.122 sec. • engine limits •