Base | Representation |
---|---|
bin | 1100000001000111110011… |
… | …0011111101111010001111 |
3 | 1201210012010111110112201011 |
4 | 3000101330303331322033 |
5 | 3212442032312301312 |
6 | 44034054110230051 |
7 | 2532431462515426 |
oct | 300217463757217 |
9 | 51705114415634 |
10 | 13213413400207 |
11 | 4234860434009 |
12 | 1594a214b5327 |
13 | 74b033bccc97 |
14 | 3397657242bd |
15 | 17daa04bbda7 |
hex | c047ccfde8f |
13213413400207 has 2 divisors, whose sum is σ = 13213413400208. Its totient is φ = 13213413400206.
The previous prime is 13213413400189. The next prime is 13213413400223. The reversal of 13213413400207 is 70200431431231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13213413400207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13213413410207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606706700103 + 6606706700104.
It is an arithmetic number, because the mean of its divisors is an integer number (6606706700104).
Almost surely, 213213413400207 is an apocalyptic number.
13213413400207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13213413400207 is an equidigital number, since it uses as much as digits as its factorization.
13213413400207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 13213413400207 its reverse (70200431431231), we get a palindrome (83413844831438).
The spelling of 13213413400207 in words is "thirteen trillion, two hundred thirteen billion, four hundred thirteen million, four hundred thousand, two hundred seven".
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