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1321353425113 is a prime number
BaseRepresentation
bin10011001110100110110…
…011010011000011011001
311200022122101120211200221
4103032212303103003121
5133122112434100423
62451004341400041
7164315240540161
oct23164663230331
94608571524627
101321353425113
1146a423619567
12194106709021
13977abcc4427
1447d4d4db5a1
15245888d5e5d
hex133a6cd30d9

1321353425113 has 2 divisors, whose sum is σ = 1321353425114. Its totient is φ = 1321353425112.

The previous prime is 1321353425107. The next prime is 1321353425131. The reversal of 1321353425113 is 3115243531231.

Together with next prime (1321353425131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1300336544329 + 21016880784 = 1140323^2 + 144972^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321353425113 - 25 = 1321353425081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1321353429113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660676712556 + 660676712557.

It is an arithmetic number, because the mean of its divisors is an integer number (660676712557).

Almost surely, 21321353425113 is an apocalyptic number.

It is an amenable number.

1321353425113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321353425113 is an equidigital number, since it uses as much as digits as its factorization.

1321353425113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32400, while the sum is 34.

Adding to 1321353425113 its reverse (3115243531231), we get a palindrome (4436596956344).

The spelling of 1321353425113 in words is "one trillion, three hundred twenty-one billion, three hundred fifty-three million, four hundred twenty-five thousand, one hundred thirteen".