Search a number
-
+
132138253454197 is a prime number
BaseRepresentation
bin11110000010110111010101…
…101010001000101101110101
3122022212021221002010022001111
4132002313111222020231311
5114304423120341013242
61145011250422155021
736555450050163544
oct3602672552105565
9568767832108044
10132138253454197
1139115578268471
12129a1341882a71
1358967788b5b93
14248b75031a15b
151042344c9c817
hex782dd5a88b75

132138253454197 has 2 divisors, whose sum is σ = 132138253454198. Its totient is φ = 132138253454196.

The previous prime is 132138253454189. The next prime is 132138253454257. The reversal of 132138253454197 is 791454352831231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121156492566321 + 10981760887876 = 11007111^2 + 3313874^2 .

It is a cyclic number.

It is not a de Polignac number, because 132138253454197 - 23 = 132138253454189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132138253454797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66069126727098 + 66069126727099.

It is an arithmetic number, because the mean of its divisors is an integer number (66069126727099).

Almost surely, 2132138253454197 is an apocalyptic number.

It is an amenable number.

132138253454197 is a deficient number, since it is larger than the sum of its proper divisors (1).

132138253454197 is an equidigital number, since it uses as much as digits as its factorization.

132138253454197 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 21772800, while the sum is 58.

The spelling of 132138253454197 in words is "one hundred thirty-two trillion, one hundred thirty-eight billion, two hundred fifty-three million, four hundred fifty-four thousand, one hundred ninety-seven".