13214004215441 has 2 divisors, whose sum is σ = 13214004215442. Its totient is φ = 13214004215440.

The previous prime is 13214004215429. The next prime is 13214004215471. The reversal of 13214004215441 is 14451240041231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12219247324816 + 994756890625 = 3495604^2 + 997375^2 .

It is a cyclic number.

It is not a de Polignac number, because 13214004215441 - 2¹⁴ = 13214004199057 is a prime.

It is a super-3 number, since 3×13214004215441³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13214004215398 and 13214004215407.

It is not a weakly prime, because it can be changed into another prime (13214004215471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607002107720 + 6607002107721.

It is an arithmetic number, because the mean of its divisors is an integer number (6607002107721).

Almost surely, 2^{13214004215441} is an apocalyptic number.

It is an amenable number.

13214004215441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13214004215441 is an equidigital number, since it uses as much as digits as its factorization.

13214004215441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 13214004215441 its reverse (14451240041231), we get a palindrome (27665244256672).

The spelling of 13214004215441 in words is "thirteen trillion, two hundred fourteen billion, four million, two hundred fifteen thousand, four hundred forty-one".