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132140342314400 = 25527411035587613
BaseRepresentation
bin11110000010111001010010…
…001010100000010110100000
3122022212111022122200101120012
4132002321102022200112200
5114304441410113030100
61145012234001504052
736555552603203150
oct3602712212402640
9568774278611505
10132140342314400
113911644a388012
12129a1825342028
135896a1c5a3434
14248b8ab906760
151042418364135
hex782e522a05a0

132140342314400 has 288 divisors, whose sum is σ = 381330248802048. Its totient is φ = 43771117363200.

The previous prime is 132140342314271. The next prime is 132140342314411. The reversal of 132140342314400 is 4413243041231.

It is a super-2 number, since 2×1321403423144002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 20854994 + ... + 26442606.

It is an arithmetic number, because the mean of its divisors is an integer number (1324063363896).

Almost surely, 2132140342314400 is an apocalyptic number.

132140342314400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132140342314400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (190665124401024).

132140342314400 is an abundant number, since it is smaller than the sum of its proper divisors (249189906487648).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132140342314400 is a wasteful number, since it uses less digits than its factorization.

132140342314400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5587784 (or 5587771 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 132140342314400 its reverse (4413243041231), we get a palindrome (136553585355631).

The spelling of 132140342314400 in words is "one hundred thirty-two trillion, one hundred forty billion, three hundred forty-two million, three hundred fourteen thousand, four hundred".