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13214050123 is a prime number
BaseRepresentation
bin11000100111001111…
…00110011101001011
31021002220120022000211
430103213212131023
5204030244100443
610023114541551
7645312400321
oct142347463513
937086508024
1013214050123
115670a9448a
1226894378b7
131327838191
148d4d67d11
1552513419d
hex3139e674b

13214050123 has 2 divisors, whose sum is σ = 13214050124. Its totient is φ = 13214050122.

The previous prime is 13214050067. The next prime is 13214050163. The reversal of 13214050123 is 32105041231.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13214050123 - 217 = 13213919051 is a prime.

It is a super-2 number, since 2×132140501232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13214050094 and 13214050103.

It is not a weakly prime, because it can be changed into another prime (13214050163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607025061 + 6607025062.

It is an arithmetic number, because the mean of its divisors is an integer number (6607025062).

Almost surely, 213214050123 is an apocalyptic number.

13214050123 is a deficient number, since it is larger than the sum of its proper divisors (1).

13214050123 is an equidigital number, since it uses as much as digits as its factorization.

13214050123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 13214050123 its reverse (32105041231), we get a palindrome (45319091354).

The spelling of 13214050123 in words is "thirteen billion, two hundred fourteen million, fifty thousand, one hundred twenty-three".