132141205504053 has 24 divisors (see below), whose sum is σ = 200963495940480. Its totient is φ = 83438062485120.

The previous prime is 132141205504019. The next prime is 132141205504079. The reversal of 132141205504053 is 350405502141231.

132141205504053 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 4 + 12 + 0 + 550 + 40 + 53 = 666.

It is not a de Polignac number, because 132141205504053 - 2⁴⁰ = 131041693876277 is a prime.

It is a super-2 number, since 2×132141205504053² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132141205503999 and 132141205504017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132141205504153) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 89735076 + ... + 91195757.

It is an arithmetic number, because the mean of its divisors is an integer number (8373478997520).

Almost surely, 2^{132141205504053} is an apocalyptic number.

It is an amenable number.

132141205504053 is a deficient number, since it is larger than the sum of its proper divisors (68822290436427).

132141205504053 is a wasteful number, since it uses less digits than its factorization.

132141205504053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180935129 (or 180935126 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 132141205504053 its reverse (350405502141231), we get a palindrome (482546707645284).

The spelling of 132141205504053 in words is "one hundred thirty-two trillion, one hundred forty-one billion, two hundred five million, five hundred four thousand, fifty-three".