Base | Representation |
---|---|
bin | 11110000010111010000101… |
… | …100111010100000000110110 |
3 | 122022212120112210220222011101 |
4 | 132002322011213110000312 |
5 | 114310000142102112204 |
6 | 1145012455355000314 |
7 | 36555613154200105 |
oct | 3602720547240066 |
9 | 568776483828141 |
10 | 132141205504054 |
11 | 3911685265819a |
12 | 129a1a2643909a |
13 | 5896b2937c046 |
14 | 248b95040003c |
15 | 104246901dea4 |
hex | 782e859d4036 |
132141205504054 has 8 divisors (see below), whose sum is σ = 203568884155008. Its totient is φ = 64284910785720.
The previous prime is 132141205504019. The next prime is 132141205504079. The reversal of 132141205504054 is 450405502141231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1321412055040542 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 892845983062 + ... + 892845983209.
It is an arithmetic number, because the mean of its divisors is an integer number (25446110519376).
Almost surely, 2132141205504054 is an apocalyptic number.
132141205504054 is a deficient number, since it is larger than the sum of its proper divisors (71427678650954).
132141205504054 is a wasteful number, since it uses less digits than its factorization.
132141205504054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1785691966310.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 132141205504054 its reverse (450405502141231), we get a palindrome (582546707645285).
The spelling of 132141205504054 in words is "one hundred thirty-two trillion, one hundred forty-one billion, two hundred five million, five hundred four thousand, fifty-four".
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