Search a number
-
+
132141205504055 = 5113676546505103
BaseRepresentation
bin11110000010111010000101…
…100111010100000000110111
3122022212120112210220222011102
4132002322011213110000313
5114310000142102112210
61145012455355000315
736555613154200106
oct3602720547240067
9568776483828142
10132141205504055
11391168526581a0
12129a1a2643909b
135896b2937c047
14248b95040003d
15104246901dea5
hex782e859d4037

132141205504055 has 16 divisors (see below), whose sum is σ = 173456199235584. Its totient is φ = 95840834693280.

The previous prime is 132141205504019. The next prime is 132141205504079. The reversal of 132141205504055 is 550405502141231.

It is not a de Polignac number, because 132141205504055 - 212 = 132141205499959 is a prime.

It is a super-2 number, since 2×1321412055040552 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3273232367 + ... + 3273272736.

It is an arithmetic number, because the mean of its divisors is an integer number (10841012452224).

Almost surely, 2132141205504055 is an apocalyptic number.

132141205504055 is a deficient number, since it is larger than the sum of its proper divisors (41314993731529).

132141205504055 is a wasteful number, since it uses less digits than its factorization.

132141205504055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6546505486.

The product of its (nonzero) digits is 120000, while the sum is 38.

Adding to 132141205504055 its reverse (550405502141231), we get a palindrome (682546707645286).

The spelling of 132141205504055 in words is "one hundred thirty-two trillion, one hundred forty-one billion, two hundred five million, five hundred four thousand, fifty-five".

Divisors: 1 5 11 55 367 1835 4037 20185 6546505103 32732525515 72011556133 360057780665 2402567372801 12012836864005 26428241100811 132141205504055