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1321414242397 is a prime number
BaseRepresentation
bin10011001110101010011…
…011010011000001011101
311200022210122000200022221
4103032222123103001131
5133122224021224042
62451014353105341
7164316606510064
oct23165233230135
94608718020287
101321414242397
1146a454988487
12194122b58251
13977bb7993a2
1447d5760d1db
152458ddead67
hex133aa6d305d

1321414242397 has 2 divisors, whose sum is σ = 1321414242398. Its totient is φ = 1321414242396.

The previous prime is 1321414242389. The next prime is 1321414242451. The reversal of 1321414242397 is 7932424141231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1209705217956 + 111709024441 = 1099866^2 + 334229^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321414242397 - 23 = 1321414242389 is a prime.

It is a super-2 number, since 2×13214142423972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1321414242307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660707121198 + 660707121199.

It is an arithmetic number, because the mean of its divisors is an integer number (660707121199).

Almost surely, 21321414242397 is an apocalyptic number.

It is an amenable number.

1321414242397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321414242397 is an equidigital number, since it uses as much as digits as its factorization.

1321414242397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 290304, while the sum is 43.

The spelling of 1321414242397 in words is "one trillion, three hundred twenty-one billion, four hundred fourteen million, two hundred forty-two thousand, three hundred ninety-seven".