Base | Representation |
---|---|
bin | 111101100010001001… |
… | …1101011010001111111 |
3 | 110122002020110002111122 |
4 | 1323010103223101333 |
5 | 4131111440324411 |
6 | 140412212341155 |
7 | 12355420545533 |
oct | 1730423532177 |
9 | 418066402448 |
10 | 132142511231 |
11 | 51050003575 |
12 | 2173a3147bb |
13 | c5cba28263 |
14 | 6577c5dbc3 |
15 | 3685ec69db |
hex | 1ec44eb47f |
132142511231 has 2 divisors, whose sum is σ = 132142511232. Its totient is φ = 132142511230.
The previous prime is 132142511203. The next prime is 132142511299. The reversal of 132142511231 is 132115241231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132142511231 - 26 = 132142511167 is a prime.
It is a super-2 number, since 2×1321425112312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132142511231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132142511201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66071255615 + 66071255616.
It is an arithmetic number, because the mean of its divisors is an integer number (66071255616).
Almost surely, 2132142511231 is an apocalyptic number.
132142511231 is a deficient number, since it is larger than the sum of its proper divisors (1).
132142511231 is an equidigital number, since it uses as much as digits as its factorization.
132142511231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 26.
Adding to 132142511231 its reverse (132115241231), we get a palindrome (264257752462).
The spelling of 132142511231 in words is "one hundred thirty-two billion, one hundred forty-two million, five hundred eleven thousand, two hundred thirty-one".
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