Base | Representation |
---|---|
bin | 1100000001001011011110… |
… | …1101011011000100111110 |
3 | 1201210021200100211021020121 |
4 | 3000102313231123010332 |
5 | 3213001043243243124 |
6 | 44034340125405154 |
7 | 2532465121542604 |
oct | 300226755330476 |
9 | 51707610737217 |
10 | 13214401540414 |
11 | 4235218197408 |
12 | 15950584097ba |
13 | 74b160846c29 |
14 | 33981aa65874 |
15 | 17db0c1092e4 |
hex | c04b7b5b13e |
13214401540414 has 4 divisors (see below), whose sum is σ = 19821602310624. Its totient is φ = 6607200770206.
The previous prime is 13214401540411. The next prime is 13214401540427. The reversal of 13214401540414 is 41404510441231.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13214401540414.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13214401540411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303600385102 + ... + 3303600385105.
It is an arithmetic number, because the mean of its divisors is an integer number (4955400577656).
Almost surely, 213214401540414 is an apocalyptic number.
13214401540414 is a deficient number, since it is larger than the sum of its proper divisors (6607200770210).
13214401540414 is an equidigital number, since it uses as much as digits as its factorization.
13214401540414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6607200770209.
The product of its (nonzero) digits is 30720, while the sum is 34.
Adding to 13214401540414 its reverse (41404510441231), we get a palindrome (54618911981645).
The spelling of 13214401540414 in words is "thirteen trillion, two hundred fourteen billion, four hundred one million, five hundred forty thousand, four hundred fourteen".
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