Search a number
-
+
13215029953 is a prime number
BaseRepresentation
bin11000100111010110…
…10101101011000001
31021002222102002002211
430103223111223001
5204031021424303
610023151542121
7645323621056
oct142353255301
937088362084
1013215029953
1156715a3664
12268982a941
131327abc168
148d514102d
1552527966d
hex313ad5ac1

13215029953 has 2 divisors, whose sum is σ = 13215029954. Its totient is φ = 13215029952.

The previous prime is 13215029939. The next prime is 13215030047. The reversal of 13215029953 is 35992051231.

13215029953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9890700304 + 3324329649 = 99452^2 + 57657^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13215029953 is a prime.

It is a super-3 number, since 3×132150299533 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13315029953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607514976 + 6607514977.

It is an arithmetic number, because the mean of its divisors is an integer number (6607514977).

Almost surely, 213215029953 is an apocalyptic number.

It is an amenable number.

13215029953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13215029953 is an equidigital number, since it uses as much as digits as its factorization.

13215029953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72900, while the sum is 40.

The spelling of 13215029953 in words is "thirteen billion, two hundred fifteen million, twenty-nine thousand, nine hundred fifty-three".