Base | Representation |
---|---|
bin | 11000100111010110… |
… | …10101101100011111 |
3 | 1021002222102002020022 |
4 | 30103223111230133 |
5 | 204031021430142 |
6 | 10023151542355 |
7 | 645323621252 |
oct | 142353255437 |
9 | 37088362208 |
10 | 13215030047 |
11 | 56715a373a |
12 | 268982a9bb |
13 | 1327abc20b |
14 | 8d5141099 |
15 | 5252796d2 |
hex | 313ad5b1f |
13215030047 has 2 divisors, whose sum is σ = 13215030048. Its totient is φ = 13215030046.
The previous prime is 13215029953. The next prime is 13215030071. The reversal of 13215030047 is 74003051231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13215030047 - 232 = 8920062751 is a prime.
It is a super-2 number, since 2×132150300472 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13215029998 and 13215030025.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13215030247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607515023 + 6607515024.
It is an arithmetic number, because the mean of its divisors is an integer number (6607515024).
Almost surely, 213215030047 is an apocalyptic number.
13215030047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13215030047 is an equidigital number, since it uses as much as digits as its factorization.
13215030047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 26.
Adding to 13215030047 its reverse (74003051231), we get a palindrome (87218081278).
The spelling of 13215030047 in words is "thirteen billion, two hundred fifteen million, thirty thousand, forty-seven".
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