Base | Representation |
---|---|
bin | 11110000011000010111000… |
… | …010100100000010101100011 |
3 | 122022220110220202011021211201 |
4 | 132003002320110200111203 |
5 | 114310124010403141103 |
6 | 1145021100240422031 |
7 | 36556366130264533 |
oct | 3603027024402543 |
9 | 568813822137751 |
10 | 132150646146403 |
11 | 3911a857653555 |
12 | 129a3820017917 |
13 | 58979a2200951 |
14 | 248c1a81594c3 |
15 | 104281cc3b51d |
hex | 7830b8520563 |
132150646146403 has 2 divisors, whose sum is σ = 132150646146404. Its totient is φ = 132150646146402.
The previous prime is 132150646146401. The next prime is 132150646146437. The reversal of 132150646146403 is 304641646051231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132150646146403 - 21 = 132150646146401 is a prime.
It is a super-3 number, since 3×1321506461464033 (a number of 43 digits) contains 333 as substring.
Together with 132150646146401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132150646146401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075323073201 + 66075323073202.
It is an arithmetic number, because the mean of its divisors is an integer number (66075323073202).
Almost surely, 2132150646146403 is an apocalyptic number.
132150646146403 is a deficient number, since it is larger than the sum of its proper divisors (1).
132150646146403 is an equidigital number, since it uses as much as digits as its factorization.
132150646146403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244160, while the sum is 46.
The spelling of 132150646146403 in words is "one hundred thirty-two trillion, one hundred fifty billion, six hundred forty-six million, one hundred forty-six thousand, four hundred three".
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