Base | Representation |
---|---|
bin | 11110000011000010111000… |
… | …100011101010110001110011 |
3 | 122022220110221000122020102021 |
4 | 132003002320203222301303 |
5 | 114310124012412340311 |
6 | 1145021100501532311 |
7 | 36556366206131332 |
oct | 3603027043526163 |
9 | 568813830566367 |
10 | 132150650121331 |
11 | 3911a859918a16 |
12 | 129a3821414097 |
13 | 58979a2c92c8a |
14 | 248c1a88b1d19 |
15 | 104281d274171 |
hex | 7830b88eac73 |
132150650121331 has 2 divisors, whose sum is σ = 132150650121332. Its totient is φ = 132150650121330.
The previous prime is 132150650121319. The next prime is 132150650121437. The reversal of 132150650121331 is 133121056051231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132150650121331 - 217 = 132150649990259 is a prime.
It is a super-2 number, since 2×1321506501213312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132150659121331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075325060665 + 66075325060666.
It is an arithmetic number, because the mean of its divisors is an integer number (66075325060666).
Almost surely, 2132150650121331 is an apocalyptic number.
132150650121331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132150650121331 is an equidigital number, since it uses as much as digits as its factorization.
132150650121331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 34.
The spelling of 132150650121331 in words is "one hundred thirty-two trillion, one hundred fifty billion, six hundred fifty million, one hundred twenty-one thousand, three hundred thirty-one".
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