Base | Representation |
---|---|
bin | 11110000011000010111000… |
… | …100011101100111010110101 |
3 | 122022220110221000122200110002 |
4 | 132003002320203230322311 |
5 | 114310124012413130401 |
6 | 1145021100502041045 |
7 | 36556366206166031 |
oct | 3603027043547265 |
9 | 568813830580402 |
10 | 132150650130101 |
11 | 3911a859924569 |
12 | 129a3821419185 |
13 | 58979a2c96c75 |
14 | 248c1a88b51c1 |
15 | 104281d276a6b |
hex | 7830b88eceb5 |
132150650130101 has 2 divisors, whose sum is σ = 132150650130102. Its totient is φ = 132150650130100.
The previous prime is 132150650129969. The next prime is 132150650130139. The reversal of 132150650130101 is 101031056051231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131993099880625 + 157550249476 = 11488825^2 + 396926^2 .
It is a cyclic number.
It is not a de Polignac number, because 132150650130101 - 210 = 132150650129077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132150650130151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075325065050 + 66075325065051.
It is an arithmetic number, because the mean of its divisors is an integer number (66075325065051).
Almost surely, 2132150650130101 is an apocalyptic number.
It is an amenable number.
132150650130101 is a deficient number, since it is larger than the sum of its proper divisors (1).
132150650130101 is an equidigital number, since it uses as much as digits as its factorization.
132150650130101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 29.
The spelling of 132150650130101 in words is "one hundred thirty-two trillion, one hundred fifty billion, six hundred fifty million, one hundred thirty thousand, one hundred one".
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