Base | Representation |
---|---|
bin | 11110000011000011010101… |
… | …001110010001100100101110 |
3 | 122022220112011112121001201122 |
4 | 132003003111032101210232 |
5 | 114310131004022133314 |
6 | 1145021220321540542 |
7 | 36556414136024462 |
oct | 3603032516214456 |
9 | 568815145531648 |
10 | 132151131052334 |
11 | 3911aa86340559 |
12 | 129a39364a4752 |
13 | 5897a4b7cc634 |
14 | 248c2127024a2 |
15 | 104284a5c228e |
hex | 7830d539192e |
132151131052334 has 4 divisors (see below), whose sum is σ = 198226696578504. Its totient is φ = 66075565526166.
The previous prime is 132151131052333. The next prime is 132151131052397. The reversal of 132151131052334 is 433250131151231.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1321511310523342 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132151131052294 and 132151131052303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132151131052333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33037782763082 + ... + 33037782763085.
It is an arithmetic number, because the mean of its divisors is an integer number (49556674144626).
Almost surely, 2132151131052334 is an apocalyptic number.
132151131052334 is a deficient number, since it is larger than the sum of its proper divisors (66075565526170).
132151131052334 is an equidigital number, since it uses as much as digits as its factorization.
132151131052334 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66075565526169.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 132151131052334 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred thirty-one million, fifty-two thousand, three hundred thirty-four".
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