Base | Representation |
---|---|
bin | 11110000011000011010101… |
… | …001110010001100100101101 |
3 | 122022220112011112121001201121 |
4 | 132003003111032101210231 |
5 | 114310131004022133313 |
6 | 1145021220321540541 |
7 | 36556414136024461 |
oct | 3603032516214455 |
9 | 568815145531647 |
10 | 132151131052333 |
11 | 3911aa86340558 |
12 | 129a39364a4751 |
13 | 5897a4b7cc633 |
14 | 248c2127024a1 |
15 | 104284a5c228d |
hex | 7830d539192d |
132151131052333 has 2 divisors, whose sum is σ = 132151131052334. Its totient is φ = 132151131052332.
The previous prime is 132151131052319. The next prime is 132151131052397. The reversal of 132151131052333 is 333250131151231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73903371243849 + 58247759808484 = 8596707^2 + 7632022^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132151131052333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132151131052033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075565526166 + 66075565526167.
It is an arithmetic number, because the mean of its divisors is an integer number (66075565526167).
Almost surely, 2132151131052333 is an apocalyptic number.
It is an amenable number.
132151131052333 is a deficient number, since it is larger than the sum of its proper divisors (1).
132151131052333 is an equidigital number, since it uses as much as digits as its factorization.
132151131052333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 34.
The spelling of 132151131052333 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred thirty-one million, fifty-two thousand, three hundred thirty-three".
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