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13215322510321 is a prime number
BaseRepresentation
bin1100000001001110111010…
…0110101001001111110001
31201210101001112210101110011
43000103232212221033301
53213004440030312241
644035011345134521
72532530003630221
oct300235646511761
951711045711404
1013215322510321
114235650041768
12159527492a441
1374b2795a3339
143398a70c0081
1517db62dc9281
hexc04ee9a93f1

13215322510321 has 2 divisors, whose sum is σ = 13215322510322. Its totient is φ = 13215322510320.

The previous prime is 13215322510279. The next prime is 13215322510343. The reversal of 13215322510321 is 12301522351231.

It is a happy number.

13215322510321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13092637640625 + 122684869696 = 3618375^2 + 350264^2 .

It is a cyclic number.

It is not a de Polignac number, because 13215322510321 - 219 = 13215321986033 is a prime.

It is not a weakly prime, because it can be changed into another prime (13215322510381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607661255160 + 6607661255161.

It is an arithmetic number, because the mean of its divisors is an integer number (6607661255161).

Almost surely, 213215322510321 is an apocalyptic number.

It is an amenable number.

13215322510321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13215322510321 is an equidigital number, since it uses as much as digits as its factorization.

13215322510321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13215322510321 its reverse (12301522351231), we get a palindrome (25516844861552).

The spelling of 13215322510321 in words is "thirteen trillion, two hundred fifteen billion, three hundred twenty-two million, five hundred ten thousand, three hundred twenty-one".