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132153440308033 is a prime number
BaseRepresentation
bin11110000011000101011110…
…110111011000101101000001
3122022220202010110212102000111
4132003011132313120231001
5114310200221204324113
61145022241413151321
736556525306255414
oct3603053667305501
9568822113772014
10132153440308033
1139120a60903541
12129a427b92b541
135898029065621
14248c39129db7b
1510429331c113d
hex78315edd8b41

132153440308033 has 2 divisors, whose sum is σ = 132153440308034. Its totient is φ = 132153440308032.

The previous prime is 132153440308013. The next prime is 132153440308037. The reversal of 132153440308033 is 330803044351231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123660249189169 + 8493191118864 = 11120263^2 + 2914308^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132153440308033 is a prime.

It is not a weakly prime, because it can be changed into another prime (132153440308037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076720154016 + 66076720154017.

It is an arithmetic number, because the mean of its divisors is an integer number (66076720154017).

Almost surely, 2132153440308033 is an apocalyptic number.

It is an amenable number.

132153440308033 is a deficient number, since it is larger than the sum of its proper divisors (1).

132153440308033 is an equidigital number, since it uses as much as digits as its factorization.

132153440308033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 132153440308033 its reverse (330803044351231), we get a palindrome (462956484659264).

The spelling of 132153440308033 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty million, three hundred eight thousand, thirty-three".