Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …110111011000101101000101 |
3 | 122022220202010110212102000122 |
4 | 132003011132313120231011 |
5 | 114310200221204324122 |
6 | 1145022241413151325 |
7 | 36556525306255421 |
oct | 3603053667305505 |
9 | 568822113772018 |
10 | 132153440308037 |
11 | 39120a60903545 |
12 | 129a427b92b545 |
13 | 5898029065625 |
14 | 248c39129db81 |
15 | 10429331c1142 |
hex | 78315edd8b45 |
132153440308037 has 2 divisors, whose sum is σ = 132153440308038. Its totient is φ = 132153440308036.
The previous prime is 132153440308033. The next prime is 132153440308049. The reversal of 132153440308037 is 730803044351231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100866488919361 + 31286951388676 = 10043231^2 + 5593474^2 .
It is a cyclic number.
It is not a de Polignac number, because 132153440308037 - 22 = 132153440308033 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132153440308033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076720154018 + 66076720154019.
It is an arithmetic number, because the mean of its divisors is an integer number (66076720154019).
Almost surely, 2132153440308037 is an apocalyptic number.
It is an amenable number.
132153440308037 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153440308037 is an equidigital number, since it uses as much as digits as its factorization.
132153440308037 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 44.
Adding to 132153440308037 its reverse (730803044351231), we get a palindrome (862956484659268).
The spelling of 132153440308037 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty million, three hundred eight thousand, thirty-seven".
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