Base | Representation |
---|---|
bin | 11110000011000101011111… |
… | …101000101001011000011111 |
3 | 122022220202011101011110211121 |
4 | 132003011133220221120133 |
5 | 114310200233011041112 |
6 | 1145022242554031411 |
7 | 36556525524110632 |
oct | 3603053750513037 |
9 | 568822141143747 |
10 | 132153453221407 |
11 | 39120a68123552 |
12 | 129a4284118567 |
13 | 589802b937287 |
14 | 248c392ca1c19 |
15 | 10429343c2407 |
hex | 78315fa2961f |
132153453221407 has 2 divisors, whose sum is σ = 132153453221408. Its totient is φ = 132153453221406.
The previous prime is 132153453221369. The next prime is 132153453221417. The reversal of 132153453221407 is 704122354351231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132153453221407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132153453221417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076726610703 + 66076726610704.
It is an arithmetic number, because the mean of its divisors is an integer number (66076726610704).
Almost surely, 2132153453221407 is an apocalyptic number.
132153453221407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153453221407 is an equidigital number, since it uses as much as digits as its factorization.
132153453221407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 43.
The spelling of 132153453221407 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred fifty-three million, two hundred twenty-one thousand, four hundred seven".
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