Base | Representation |
---|---|
bin | 11110000011000110010010… |
… | …111001010111100111001001 |
3 | 122022220211101022110002210012 |
4 | 132003012102321113213021 |
5 | 114310204013142234311 |
6 | 1145022504155201305 |
7 | 36556556036141513 |
oct | 3603062271274711 |
9 | 568824338402705 |
10 | 132154313243081 |
11 | 3912136962a568 |
12 | 129a4484146235 |
13 | 5898137b73c3c |
14 | 248c4351b2bb3 |
15 | 1042984b5378b |
hex | 783192e579c9 |
132154313243081 has 2 divisors, whose sum is σ = 132154313243082. Its totient is φ = 132154313243080.
The previous prime is 132154313243063. The next prime is 132154313243159. The reversal of 132154313243081 is 180342313451231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96179700765625 + 35974612477456 = 9807125^2 + 5997884^2 .
It is a cyclic number.
It is not a de Polignac number, because 132154313243081 - 234 = 132137133373897 is a prime.
It is a super-2 number, since 2×1321543132430812 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132154313243581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66077156621540 + 66077156621541.
It is an arithmetic number, because the mean of its divisors is an integer number (66077156621541).
Almost surely, 2132154313243081 is an apocalyptic number.
It is an amenable number.
132154313243081 is a deficient number, since it is larger than the sum of its proper divisors (1).
132154313243081 is an equidigital number, since it uses as much as digits as its factorization.
132154313243081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 41.
The spelling of 132154313243081 in words is "one hundred thirty-two trillion, one hundred fifty-four billion, three hundred thirteen million, two hundred forty-three thousand, eighty-one".
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