Base | Representation |
---|---|
bin | 11110000011000110010010… |
… | …111001010111101000010111 |
3 | 122022220211101022110002220002 |
4 | 132003012102321113220113 |
5 | 114310204013142240114 |
6 | 1145022504155201515 |
7 | 36556556036141654 |
oct | 3603062271275027 |
9 | 568824338402802 |
10 | 132154313243159 |
11 | 3912136962a629 |
12 | 129a448414629b |
13 | 5898137b73c9c |
14 | 248c4351b2c2b |
15 | 1042984b537de |
hex | 783192e57a17 |
132154313243159 has 2 divisors, whose sum is σ = 132154313243160. Its totient is φ = 132154313243158.
The previous prime is 132154313243081. The next prime is 132154313243207. The reversal of 132154313243159 is 951342313451231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132154313243159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132154313249159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66077156621579 + 66077156621580.
It is an arithmetic number, because the mean of its divisors is an integer number (66077156621580).
Almost surely, 2132154313243159 is an apocalyptic number.
132154313243159 is a deficient number, since it is larger than the sum of its proper divisors (1).
132154313243159 is an equidigital number, since it uses as much as digits as its factorization.
132154313243159 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1166400, while the sum is 47.
The spelling of 132154313243159 in words is "one hundred thirty-two trillion, one hundred fifty-four billion, three hundred thirteen million, two hundred forty-three thousand, one hundred fifty-nine".
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